. COBOL HELLO WORLD. Example 1 -. by surender, www.suren.space. IDENTIFICATION DIVISION. ENVIRONMENT DIVISION. PROCEDURE DIVISION. DISPLAY 'HELLO WORLD!'. PRG2 Write a program to accept the string from user and to display the same. C Program to Check the Given String is Palindrome Example 1. This program for string palindrome in c allows the user to enter a string (or character array), and a character value. Next, it will check whether the user-specified string is a palindrome string or not.
Learn to check if a given string is palindrome string with simple java programs using stack, queue or simple loops. In simplest words, a string is palindrome if it is equal to it’s reverse string.
A palindrome is a word, phrase, number, or other sequence of units that may be read the same way in either direction, generally if used comma, separators or other word dividers are ignored.
To check palindrome, we can pick the characters (one by one) from start and end of string and start comparing to each other.
Rather than comparing chars from start and end, we can also find the reverse string of the given string and compare both strings. If both strings are same, they are palindrome.
In this tutorial, we will see the examples of both approaches.
This method uses the first approach given above.
StringBuilder.reverse()
method is shortest way to reverse a string using library functions.
Using stack’s push()
and pop()
methods, we can build a reverse string for a given string. Then we compare both strings.
Using Queue’s add()
and remove()
methods, we can build a reverse string for a given string. Then we compare both strings.
This is simplest approach which simply iterated the char array backwards and creates the string by appending chars to produce reverse string.
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A palindrome is a string, which when read in both forward and backward ways is the same.
Example:
Example: lol, pop, radar, madam, etc.
To check if a string is a palindrome or not, a string needs to be compared with the reverse of itself.
Consider a palindrome string: lol,
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index: 0 1 2
value: l o l
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To compare it with the reverse of itself, the following logic is used: